Class 7 : Maths β Lesson 1. Large Numbers Around Us
EXPLANATION AND ANALYSIS
π΅ Introduction: Large Numbers in Everyday Life
π§ In our daily activities, we usually deal with small numbers such as the number of books, students, or money spent on simple items. However, there are many situations around us where numbers become very large. Such numbers appear when we read newspapers, watch news, or study subjects like science and geography.
πΏ Examples from daily life
π΅ Population of a country is counted in crores
π’ Distance between planets is measured in thousands or lakhs of kilometres
π‘ Government budgets involve very large numbers
π΄ Digital data is measured in gigabytes and terabytes
β‘οΈ To understand these facts clearly, we must learn how to read, write, compare, and estimate large numbers correctly. This chapter introduces these ideas.
π’ Place Value: The Basis of Large Numbers
π§ Every digit in a number has a value depending on its position. This is called the place value of the digit.
π Example
In the number 4,36,728, the digit 3 represents 30,000.
π‘ Concept:
Each place to the left has a value ten times greater than the place to its right.
π΅ Indian Place Value System
π§ In India, we follow the Indian place value system.
π΅ Ones
π’ Tens
π‘ Hundreds
π΄ Thousands
π΅ Lakhs
π’ Crores
π Example
The number 6,48,25,309 is read as
Six crore forty-eight lakh twenty-five thousand three hundred nine
βοΈ Note:
In the Indian system, commas are placed after the first three digits from the right and then after every two digits.
π’ International Place Value System
π Many other countries use the International place value system.
π΅ Ones
π’ Tens
π‘ Hundreds
π΄ Thousands
π΅ Millions
π’ Billions
π Example
The number 64,825,309 is read as
Sixty-four million eight hundred twenty-five thousand three hundred nine
π‘ Concept:
Indian system uses lakh and crore, while International system uses million and billion.
π‘ Reading Large Numbers
π§ To read large numbers correctly, we should follow a fixed method.
π΅ Place commas correctly
π’ Start reading from the leftmost group
π‘ Use correct place value names
π Example
5,03,07,418 is read as
Five crore three lakh seven thousand four hundred eighteen
π΄ Common mistake:
Reading digits one by one instead of using place values.
π΅ Writing Large Numbers in Numerals
π§ While writing numbers given in words, it is important to identify place value words like thousand, lakh, and crore.
π Example
Seven crore four lakh two thousand sixty-five
7,04,02,065
βοΈ Note:
Zeros are very important in large numbers. Missing a zero changes the value of the number.
π’ Comparing Large Numbers
π§ Large numbers can be compared easily by following a fixed order.
π΅ Step 1: Compare the number of digits
π’ Step 2: If digits are equal, compare digits from the left
π‘ Step 3: The number with the greater digit is larger
π Example
Compare 8,34,912 and 8,29,745
Both have six digits
At the ten-thousands place, 3 is greater than 2
So 8,34,912 is greater
π‘ Ordering Large Numbers
π§ Ordering means arranging numbers in a particular sequence.
π΅ Ascending order means smallest to greatest
π’ Descending order means greatest to smallest
π Example
2,84,679, 2,96,540, 3,10,428 in ascending order
2,84,679 < 2,96,540 < 3,10,428
π΅ Estimation and Rounding Off
π§ Estimation gives an approximate value of a number when an exact value is not required.
π΅ Look at the digit to the right
π’ If it is less than 5, round down
π‘ If it is 5 or more, round up
π Example
Round 6,72,418 to the nearest thousand
The hundreds digit is 4
The rounded value is 6,72,000
π‘ Concept:
Estimation makes calculations quicker and easier.
π’ Use of Large Numbers in Daily Life
πΏ Large numbers are used in many fields.
π΅ Population studies
π’ Space science
π‘ Banking and finance
π΄ Government planning
π΅ Digital storage
π Example
The distance between Earth and the Moon is about 3,84,400 kilometres.
π΄ Common Errors to Avoid
π΄ Wrong placement of commas
π΄ Mixing Indian and International systems
π΄ Forgetting zeros
π΄ Incorrect reading of place values
βοΈ Note:
Always recheck comma placement before reading or writing a number.
π’ Importance of Learning Large Numbers
π§ Understanding large numbers helps us interpret real-world data correctly.
π΅ Builds strong number sense
π’ Helps in science and geography
π‘ Useful for higher mathematics
π΄ Important for everyday understanding
π Summary
π΅ Large numbers help us describe very big quantities
π’ Place value gives meaning to each digit
π‘ Indian and International systems are different
π΄ Correct reading and writing depend on comma placement
π΅ Numbers can be compared and ordered easily
π’ Estimation gives approximate values
π‘ Large numbers are used widely in daily life
π Quick Recap
π Quick Recap
π΅ Large numbers represent huge quantities
π’ Place value decides digit value
π‘ Indian system uses lakh and crore
π΄ International system uses million and billion
π΅ Estimation simplifies calculations
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TEXTBOOK QUESTIONS
πΏ 1.1 A LAKH VARIETIES!
π β Question 1.
According to the 2011 Census, the population of the town of Chintamani was about 75,000. How much less than one lakh is 75,000?
π β
Answer:
πΉ One lakh = 1,00,000
πΉ Given population = 75,000
πΉ Difference = 1,00,000 β 75,000
πΈ = 25,000
βοΈ Final: 75,000 is 25,000 less than one lakh.
π β Question 2.
The estimated population of Chintamani in the year 2024 is 1,06,000. How much more than one lakh is 1,06,000?
π β
Answer:
πΉ One lakh = 1,00,000
πΉ Estimated population = 1,06,000
πΉ Difference = 1,06,000 β 1,00,000
πΈ = 6,000
βοΈ Final: 1,06,000 is 6,000 more than one lakh.
π β Question 3.
By how much did the population of Chintamani increase from 2011 to 2024?
π β
Answer:
πΉ Population in 2011 = 75,000
πΉ Population in 2024 = 1,06,000
πΉ Increase = 1,06,000 β 75,000
πΈ = 31,000
βοΈ Final: The population increased by 31,000 from 2011 to 2024.
πΏ 1.2 LAND OF TENS
π β Figure it Out (a)
For the number 8300, write expressions for at least two different ways to obtain the number through button clicks.
π β
Answer:
πΉ Way 1: (83 Γ 100) = 8300
πΉ Way 2: (8 Γ 1000) + (3 Γ 100) = 8300
π β Figure it Out (b)
For the number 40629, write expressions for at least two different ways to obtain the number through button clicks.
π β
Answer:
πΉ Way 1: (40 Γ 1000) + (6 Γ 100) + (2 Γ 10) + (9 Γ 1) = 40629
πΉ Way 2: (4 Γ 10000) + (62 Γ 10) + (9 Γ 1) = 40629
π β Figure it Out (c)
For the number 56354, write expressions for at least two different ways to obtain the number through button clicks.
π β
Answer:
πΉ Way 1: (56 Γ 1000) + (3 Γ 100) + (5 Γ 10) + (4 Γ 1) = 56354
πΉ Way 2: (5 Γ 10000) + (63 Γ 100) + (5 Γ 10) + (4 Γ 1) = 56354
π β Figure it Out (d)
For the number 66666, write expressions for at least two different ways to obtain the number through button clicks.
π β
Answer:
πΉ Way 1: (6 Γ 10000) + (6 Γ 1000) + (6 Γ 100) + (6 Γ 10) + (6 Γ 1) = 66666
πΉ Way 2: (66 Γ 1000) + (6 Γ 100) + (6 Γ 10) + (6 Γ 1) = 66666
π β Figure it Out (e)
For the number 367813, write expressions for at least two different ways to obtain the number through button clicks.
π β
Answer:
πΉ Way 1: (3 Γ 100000) + (6 Γ 10000) + (7 Γ 1000) + (8 Γ 100) + (1 Γ 10) + (3 Γ 1) = 367813
πΉ Way 2: (367 Γ 1000) + (8 Γ 100) + (1 Γ 10) + (3 Γ 1) = 367813
π β Question 1.
For the numbers in the previous exercise, find out how to get each number by making the smallest number of button clicks and write the expression.
π β
Answer:
πΉ 8300
πΈ (8 Γ 1000) + (3 Γ 100) = 8300
πΉ 40629
πΈ (4 Γ 10000) + (0 Γ 1000) + (6 Γ 100) + (2 Γ 10) + (9 Γ 1) = 40629
πΉ 56354
πΈ (5 Γ 10000) + (6 Γ 1000) + (3 Γ 100) + (5 Γ 10) + (4 Γ 1) = 56354
πΉ 66666
πΈ (6 Γ 10000) + (6 Γ 1000) + (6 Γ 100) + (6 Γ 10) + (6 Γ 1) = 66666
πΉ 367813
πΈ (3 Γ 100000) + (6 Γ 10000) + (7 Γ 1000) + (8 Γ 100) + (1 Γ 10) + (3 Γ 1) = 367813
π β Question 2.
Do you see any connection between each number and the corresponding smallest number of button clicks?
π β
Answer:
πΉ The smallest number of button clicks is obtained by using the place value of each digit.
πΉ Each digit tells how many times a particular place-value button is pressed.
πΉ This avoids unnecessary extra button presses and gives the minimum total clicks.
π β Question 3.
If you notice, the expressions for the least button clicks also give the Indian place value notation of the numbers. Think about why this is so.
π β
Answer:
πΉ Indian place value notation breaks a number into digits multiplied by their place values.
πΉ Creative Chittiβs buttons exactly match these place values (+1, +10, +100, +1000, β¦).
πΉ Therefore, using the least button clicks naturally follows the Indian place value system.
πΏ 1.3 OF CRORES AND CRORES!
π β Question 1.
Read the following numbers in Indian place value notation and write their number names in both the Indian and American systems.
π β
Answer:
πΉ (a) 4050678
πΈ Indian system: Forty lakh fifty thousand six hundred seventy eight
πΈ American system: Four million fifty thousand six hundred seventy eight
πΉ (b) 48121620
πΈ Indian system: Four crore eighty one lakh twenty one thousand six hundred twenty
πΈ American system: Forty eight million one hundred twenty one thousand six hundred twenty
πΉ (c) 20022002
πΈ Indian system: Two crore two thousand two
πΈ American system: Twenty million twenty two thousand two
πΉ (d) 246813579
πΈ Indian system: Twenty four crore sixty eight lakh thirteen thousand five hundred seventy nine
πΈ American system: Two hundred forty six million eight hundred thirteen thousand five hundred seventy nine
πΉ (e) 345000543
πΈ Indian system: Thirty four crore fifty lakh five hundred forty three
πΈ American system: Three hundred forty five million five hundred forty three
πΉ (f) 1020304050
πΈ Indian system: One hundred two crore three lakh four thousand fifty
πΈ American system: One billion twenty million three hundred four thousand fifty
π β Question 2.
Write the following numbers in Indian place value notation.
π β
Answer:
πΉ (a) One crore one lakh one thousand ten
πΈ 1,01,01,010
πΉ (b) One billion one million one thousand one
πΈ 1,00,10,01,001
πΉ (c) Ten crore twenty lakh thirty thousand forty
πΈ 10,20,30,040
πΉ (d) Nine billion eighty million seven hundred thousand six hundred
πΈ 90,80,07,00,600
π β Question 3.
Compare and write β<β, β>β or β=β.
π β
Answer:
πΉ (a) 30 thousand < 3 lakhs
πΉ (b) 500 lakhs = 5 million
πΉ (c) 800 thousand < 8 million
πΉ (d) 640 crore > 60 billion
πΏ 1.5 PATTERNS IN PRODUCTS
π β Figure it Out β Question 1
Find quick ways to calculate these products.
π β
Answer:
πΉ (a) 2 Γ 1768 Γ 50
πΈ (2 Γ 50) Γ 1768 = 100 Γ 1768 = 176800
πΉ (b) 72 Γ 125
πΈ 125 = 1000 / 8
πΈ 72 Γ (1000 / 8) = 9 Γ 1000 = 9000
πΉ (c) 125 Γ 40 Γ 8 Γ 25
πΈ (125 Γ 8) Γ (40 Γ 25)
πΈ 1000 Γ 1000 = 1000000
π β Figure it Out β Question 2
Calculate these products quickly.
π β
Answer:
πΉ (a) 25 Γ 12
πΈ (100 / 4) Γ 12 = 300
βοΈ Final: 300
πΉ (b) 25 Γ 240
πΈ (100 / 4) Γ 240 = 6000
βοΈ Final: 6000
πΉ (c) 250 Γ 120
πΈ (1000 / 4) Γ 120 = 30000
βοΈ Final: 30000
πΉ (d) 2500 Γ 12
πΈ (10000 / 4) Γ 12 = 30000
βοΈ Final: 30000
πΉ (e) _____ Γ _____ = 12000000
πΈ 12000 Γ 1000 = 12000000
πΏ 1.6 DID YOU EVER WONDER…?
π β Question 1
Using all digits from 0β9 exactly once (the first digit cannot be 0) to create a 10-digit number, write theβ
(a) Largest multiple of 5
(b) Smallest even number
π β Answer:
πΉ (a) Largest multiple of 5
πΈ A multiple of 5 must end in 0 or 5.
πΈ To make the number largest, place the largest digits in the highest places.
πΈ Ending with 0 gives a larger number than ending with 5.
πΈ Arrange remaining digits from 9 to 1 in descending order.
βοΈ Final: 9876543210
πΉ (b) Smallest even number
Smallest even number
π β
Answer:
πΉ The number must use digits 0β9 exactly once, and the first digit cannot be 0.
πΉ To make it smallest, keep the smallest digits as early as possible: start with 1, then 0, then 2, 3, 4, 5, 6, 7.
πΉ The last digit must be even, so place 8 at the end and keep 9 just before it.
π β Final: 1023456798
π β Question 2
The number 10,30,285 in words is Ten lakhs thirty thousand two hundred eighty five, which has 43 letters. Give a 7-digit number name which has the maximum number of letters.
π β Answer:
πΉ Comparing long 7-digit number names shows that the word βseventyβ (7 letters) repeated many times gives more letters than βninetyβ (6 letters).
πΉ The number 7,777,777 uses seventy and seven repeatedly along with lakh, thousand, and hundred, making its name very long.
πΉ In words (Indian system):
Seventy seven lakh seventy seven thousand seven hundred seventy seven
π β Final: 7,777,777
π β Question 3
Write a 9-digit number where exchanging any two digits results in a bigger number. How many such numbers exist?
π β Answer:
πΉ For the number to increase after any exchange, the original number must be:
πΈ Arranged in strictly increasing order from left to right.
πΉ Smallest digits on the left, largest on the right.
πΉ Example:
πΈ 123456789
πΉ Any swap will move a larger digit to a higher place value, making the number larger.
πΉ Count of such numbers:
πΈ Only one such arrangement is possible using digits 1β9 once.
βοΈ Final:
πΉ Number: 123456789
πΉ Total such numbers: 1
π β Question 4
Strike out 10 digits from the number 12345123451234512345 so that the remaining number is as large as possible.
π β
Answer:
πΉ We must delete 10 digits and keep 10 digits in the same order (a subsequence).
πΉ To maximize the remaining 10-digit number, keep the earliest possible high digits (5s), while still leaving enough digits to complete 10 places.
πΉ The largest possible remaining 10-digit number is obtained by keeping digits that form:
π β Final: 5534512345
π β Question 5
The words βzeroβ and βoneβ share letters βeβ and βoβ. The words βoneβ and βtwoβ share a letter βoβ, and the words βtwoβ and βthreeβ also share a letter βtβ. How far do you have to count to find two consecutive numbers which do not share an English letter in common?
π β
Answer:
πΉ Checking consecutive number-names in standard English spelling shows that every consecutive pair shares at least one common letter.
πΉ This overlap continues because the same letters keep recurring in number words across ones, tens, hundreds, thousands, etc.
βοΈ Final: You cannot find such a pair of consecutive numbers (so there is no finite counting point where this happens).
π β Question 6
Suppose you write down all the numbers 1, 2, 3, 4, …, 9, 10, 11, …
The tenth digit you write is β1β and the eleventh digit is β0β, as part of the number 10.
(a) What would the 1000th digit be? At which number would it occur?
(b) What number would contain the millionth digit?
(c) When would you have written the digit β5β for the 5000th time?
π β Answer:
πΉ (a) 1000th digit
πΈ Digits from 1 to 9 = 9
πΈ Digits from 10 to 99 = 90 Γ 2 = 180
πΈ Total digits up to 99 = 9 + 180 = 189
πΈ Position inside 3-digit numbers = 1000 β 189 = 811
πΈ Each 3-digit number gives 3 digits
πΈ Number offset = (811 β 1) Γ· 3 = 270
πΈ Digit position inside the number = (811 β 1) mod 3 = 0 (first digit)
πΈ Number = 100 + 270 = 370
πΈ First digit of 370 = 3
βοΈ Final: 1000th digit is 3, and it occurs in the number 370
πΉ (b) millionth digit
πΈ Digits up to 9 = 9
πΈ Digits from 10 to 99 = 180
πΈ Digits from 100 to 999 = 900 Γ 3 = 2700
πΈ Total up to 999 = 9 + 180 + 2700 = 2889
πΈ Digits from 1000 to 9999 = 9000 Γ 4 = 36000
πΈ Total up to 9999 = 2889 + 36000 = 38889
πΈ Digits from 10000 to 99999 = 90000 Γ 5 = 450000
πΈ Total up to 99999 = 38889 + 450000 = 488889
πΈ Millionth position inside 6-digit numbers = 1000000 β 488889 = 511111
πΈ Each 6-digit number gives 6 digits
πΈ Number offset = (511111 β 1) Γ· 6 = 85185
πΈ Number = 100000 + 85185 = 185185
βοΈ Final: The millionth digit is contained in the number 185185
πΉ (c) digit β5β for the 5000th time
π β
Answer:
πΉ Count of digit β5β written from 1 up to 13494 is 4999.
πΉ The next number 13495 adds one more β5β, making the total 5000.
βοΈ Final: The digit β5β is written for the 5000th time while writing the number 13495.
π β Question 7
A calculator has only β+10,000β and β+100β buttons. Write an expression describing the number of button clicks to be made for the following numbers:
(a) 20,800
(b) 92,100
(c) 1,20,500
(d) 65,30,000
(e) 70,25,700
π β Answer:
πΉ (a) 20,800
πΈ 2 Γ 10,000 = 20,000
πΈ 8 Γ 100 = 800
πΈ 20,000 + 800 = 20,800
π β
Final: 2 clicks of +10,000 and 8 clicks of +100
πΉ (b) 92,100
πΈ 9 Γ 10,000 = 90,000
πΈ 21 Γ 100 = 2,100
πΈ 90,000 + 2,100 = 92,100
π β
Final: 9 clicks of +10,000 and 21 clicks of +100
πΉ (c) 1,20,500
πΈ 12 Γ 10,000 = 1,20,000
πΈ 5 Γ 100 = 500
πΈ 1,20,000 + 500 = 1,20,500
π β
Final: 12 clicks of +10,000 and 5 clicks of +100
πΉ (d) 65,30,000
πΈ 653 Γ 10,000 = 65,30,000
π β
Final: 653 clicks of +10,000 and 0 clicks of +100
πΉ (e) 70,25,700
πΈ 702 Γ 10,000 = 70,20,000
πΈ 57 Γ 100 = 5,700
πΈ 70,20,000 + 5,700 = 70,25,700
π β
Final: 702 clicks of +10,000 and 57 clicks of +100
π β Question 8
How many lakhs make a billion?
π β
Answer:
πΉ 1 lakh = 100,000
πΉ 1 billion = 1,000,000,000
πΉ Number of lakhs in a billion = 1,000,000,000 Γ· 100,000 = 10,000
βοΈ Final: 10,000 lakhs
π β Question 9
You are given two sets of number cards numbered from 1β9. Place a number card in each box below to get the (a) largest possible sum
(b) smallest possible difference of the two resulting numbers.
π β Answer:
πΉ (a) Largest possible sum
πΈ Make both numbers as large as possible by placing the largest digits in the highest places (each set used separately).
βοΈ Final: 7-digit number = 9876543, 5-digit number = 98765
πΉ (b) Smallest possible difference
πΈ To minimize the difference, make the 7-digit number as small as possible and the 5-digit number as large as possible (each from its own set).
βοΈ Final: 7-digit number = 1234567, 5-digit number = 98765
π β Question 10
You are given some number cards; 4000, 13000, 300, 70000, 150000, 20, 5. Using the cards get as close as you can to the numbers below using any operation you want. Each card can be used only once for making a particular number.
(a) 1,10,000: Closest I could make is 4000 Γ (20 + 5) + 13000
= 1,13,000
(b) 2,00,000:
(c) 5,80,000:
(d) 12,45,000:
(e) 20,90,800:
π β
Answer:
πΉ (b) 2,00,000
πΈ 150000 + 70000 = 220000
πΈ 4000 Γ 5 = 20000
πΈ 220000 β 20000 = 200000
π β
Final: 150000 + 70000 β (4000 Γ 5) = 2,00,000
πΉ (c) 5,80,000
πΈ 70000 Γ 5 = 350000
πΈ 4000 Γ 20 = 80000
πΈ 150000 + 350000 = 500000
πΈ 500000 + 80000 = 580000
π β
Final: 150000 + (70000 Γ 5) + (4000 Γ 20) = 5,80,000
πΉ (d) 12,45,000 (closest)
πΈ 70000 + 150000 = 220000
πΈ 220000 + 13000 = 233000
πΈ 233000 Γ 5 = 1165000
πΈ 4000 Γ 20 = 80000
πΈ 1165000 + 80000 = 1245000
πΈ 1245000 + 300 = 1245300
πΈ Difference from 12,45,000 = 1245300 β 1245000 = 300
π β
Final: 5 Γ (150000 + 70000 + 13000) + (4000 Γ 20) + 300 = 12,45,300 (300 more)
πΉ (e) 20,90,800 (closest)
πΈ 13000 + 150000 = 163000
πΈ 163000 Γ 5 = 815000
πΈ 20 + 4000 = 4020
πΈ 4020 Γ 300 = 1206000
πΈ 1206000 + 70000 = 1276000
πΈ 815000 + 1276000 = 2091000
πΈ Difference from 20,90,800 = 2091000 β 2090800 = 200
π β
Final: 5 Γ (150000 + 13000) + (300 Γ (4000 + 20)) + 70000 = 20,91,000 (200 more)
π β Question 11
Find out how many coins should be stacked to match the height of the Statue of Unity. Assume each coin is 1 mm thick.
π β
Answer:
πΉ Height of Statue of Unity = 182 m
πΉ 1 mm = 0.001 m
πΈ Number of coins = 182 Γ· 0.001
πΈ Number of coins = 182000
π β
Final: 1,82,000 coins
π β Question 12
Grey-headed albatrosses have a roughly 7-feet wide wingspan. They are known to migrate across several oceans. Albatrosses can cover about 900β1000 km in a day. One of the longest single trips recorded is about 12,000 km. How many days would such a trip take to cross the Pacific Ocean approximately?
π β
Answer:
πΉ Fast estimate (1000 km/day):
πΈ Days = 12000 Γ· 1000
πΈ Days = 12
πΉ Slow estimate (900 km/day):
πΈ Days = 12000 Γ· 900
πΈ Days = 13.33 (approx)
π β Final: Approximately 12 to 14 days
π β Question 13
A bar-tailed godwit holds the record for the longest recorded non-stop flight. It travelled 13,560 km from Alaska to Australia without stopping. Its journey started on 13 October 2022 and continued for about 11 days. Find out the approximate distance it covered every day. Find out the approximate distance it covered every hour.
π β
Answer:
πΉ Approximate distance per day
πΈ Total distance = 13560 km
πΈ Total time = 11 days
πΈ Distance per day = 13560/11 km
πΈ Distance per day = 1232.727… km
π β
Final: Approximately 1233 km per day
πΉ Approximate distance per hour
πΈ Total hours in 11 days = 11 Γ 24
πΈ Total hours = 264
πΈ Distance per hour = 13560/264 km
πΈ Distance per hour = 51.3636… km
π β
Final: Approximately 51 km per hour
π β Question 14
Bald eagles are known to fly as high as 4500β6000 m above the ground level. Mount Everest is about 8850 m high. Aeroplanes can fly as high as 10,000β12,800 m. How many times bigger are these heights compared to Somuβs building?
π β Answer:
πΉ From the lesson context, Somuβs building height = 10 m.
πΉ Bald eagles
πΈ 4500 Γ· 10 = 450
πΈ 6000 Γ· 10 = 600
π β
Final: Bald eagles fly about 450β600 times higher than Somuβs building.
πΉ Mount Everest
πΈ 8850 Γ· 10 = 885
π β
Final: Mount Everest is about 885 times higher than Somuβs building.
πΉ Aeroplanes
πΈ 10000 Γ· 10 = 1000
πΈ 12800 Γ· 10 = 1280
π β
Final: Aeroplanes fly about 1000β1280 times higher than Somuβs building.
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OTHER IMPORTANT QUESTIONS
( MODEL QUESTION PAPER )
ESPECIALLY MADE FROM THIS CHAPTER ONLY
π΅ Section A β Very Short Answer (1 Γ 6 = 6 marks)
π β Question 1
What is the place value of 7 in the number 7,53,214?
π β
Answer:
πΉ The digit 7 is in the lakh place
πΉ Place value of 7 = 7 Γ 1,00,000
πΉ Place value = 7,00,000
π β Question 2
Write the smallest 6-digit number.
π β
Answer:
πΉ The smallest 6-digit number is 1,00,000
π β Question 3
How many zeros are there in one crore?
π β
Answer:
πΉ One crore has 7 zeros
π β Question 4
Write 3,45,00,000 in words (Indian system).
π β
Answer:
πΉ Three crore forty-five lakh
π β Question 5
Which number is greater: 9,87,654 or 9,78,456?
π β
Answer:
πΉ Both numbers have 6 digits
πΉ At the ten-thousands place, 8 > 7
πΉ 9,87,654 is greater
π β Question 6
Round 6,48,372 to the nearest thousand.
π β
Answer:
πΉ Hundreds digit is 3
πΉ Rounded value = 6,48,000
π’ Section B β Short Answer I (2 Γ 6 = 12 marks)
π β Question 7
Write the place value of each digit in 4,62,815.
π β
Answer:
πΉ 4 = 4,00,000
πΉ 6 = 60,000
πΉ 2 = 2,000
πΉ 8 = 800
πΉ 1 = 10
πΉ 5 = 5
π β Question 8
Write in numerals: Seven crore eight lakh six thousand forty-two.
π β
Answer:
πΉ Seven crore = 7,00,00,000
πΉ Eight lakh = 8,00,000
πΉ Six thousand = 6,000
πΉ Forty-two = 42
πΉ Number = 7,08,06,042
π β Question 9
Arrange in ascending order: 3,45,678; 3,54,768; 3,47,568.
π β
Answer:
πΉ Compare digit by digit from left
πΉ Ascending order
πΉ 3,45,678 < 3,47,568 < 3,54,768
π β Question 10
Write 5,03,08,019 in words.
π β
Answer:
πΉ Five crore three lakh eight thousand nineteen
π β Question 11
Find the difference between the Indian and International place value systems.
π β
Answer:
πΉ Indian system uses lakh and crore
πΉ International system uses million and billion
π β Question 12
Round 9,84,216 to the nearest ten thousand.
π β
Answer:
πΉ Thousands digit is 4
πΉ Rounded value = 9,80,000
π‘ Section C β Short Answer II (3 Γ 10 = 30 marks)
π β Question 13
Write the number name of 6,08,45,219.
π β
Answer:
πΉ Six crore eight lakh forty-five thousand two hundred nineteen
π β Question 14
Compare 8,25,416 and 8,52,164 using place value.
π β
Answer:
πΉ Both numbers have 6 digits
πΉ At the ten-thousands place, 2 < 5
πΉ 8,52,164 is greater
π β Question 15
Write in numerals: Ninety-two million four hundred six thousand eight.
π β
Answer:
πΉ Ninety-two million = 92,000,000
πΉ Four hundred six thousand = 406,000
πΉ Eight = 8
πΉ Number = 92,406,008
π β Question 16
Round 7,48,962 to the nearest lakh.
π β
Answer:
πΉ Ten-thousands digit is 4
πΉ Rounded value = 7,00,000
π β Question 17
Write any three uses of large numbers in daily life.
π β
Answer:
πΉ Population counting
πΉ Government budgeting
πΉ Distance measurement in space
π β Question 18
Write the expanded form of 5,03,207.
π β
Answer:
πΉ 5,00,000 + 3,000 + 200 + 7
π β Question 19
Write the successor of 9,99,999.
π β
Answer:
πΉ Successor = 10,00,000
π β Question 20
Explain why estimation is useful.
π β
Answer:
πΉ It makes calculations easier
πΉ It saves time
πΉ It gives a close approximate value
π β Question 21
Write the number with 6 in lakh place and 4 in hundred place.
π β
Answer:
πΉ One such number is 6,00,400
π β Question 22
What is the face value of 8 in 8,73,945?
π β
Answer:
πΉ Face value of 8 is 8
π΄ Section D β Long Answer (4 Γ 8 = 32 marks)
π β Question 23
Write the number 7,84,26,513 in expanded form and words.
π β
Answer:
πΉ Expanded form
πΈ 7,00,00,000 + 80,00,000 + 4,00,000 + 20,000 + 6,000 + 500 + 10 + 3
πΉ In words
πΈ Seven crore eighty-four lakh twenty-six thousand five hundred thirteen
π β Question 24
Arrange 6,48,921; 6,84,219; 6,49,218 in descending order.
π β
Answer:
πΉ Compare from leftmost digit
πΉ Descending order
πΈ 6,84,219 > 6,49,218 > 6,48,921
π β Question 25
Explain the Indian place value system with an example.
π β
Answer:
πΉ Indian system uses ones, tens, hundreds, thousands, lakhs, crores
πΉ Example: 3,45,67,218
πΈ Three crore forty-five lakh sixty-seven thousand two hundred eighteen
π β Question 26
Round 9,63,417 to the nearest ten thousand and explain the steps.
π β
Answer:
πΉ Ten-thousands digit is 6
πΉ Thousands digit is 3
πΉ Rounded value = 9,60,000
π β Question 27
Write five mistakes students should avoid while dealing with large numbers.
π β
Answer:
πΉ Wrong comma placement
πΉ Mixing number systems
πΉ Missing zeros
πΉ Wrong rounding
πΉ Incorrect reading
π β Question 28
Write the predecessor and successor of 10,00,000.
π β
Answer:
πΉ Predecessor = 9,99,999
πΉ Successor = 10,00,001
π β Question 29
Explain how large numbers help us understand real-world data.
π β
Answer:
πΉ Used in population data
πΉ Used in science and space
πΉ Used in economics and planning
π β Question 30
Write 8,03,47,615 in words and international system.
π β
Answer:
πΉ Indian system
πΈ Eight crore three lakh forty-seven thousand six hundred fifteen
πΉ International system
πΈ Eighty million three hundred forty-seven thousand six hundred fifteen.
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