Class 6, Maths ( English )

Class 6 : Maths ( English ) – Lesson 6. Perimeter and Area

EXPLANATION AND ANALYSIS

🌿 1. Introduction: Measuring Boundaries and Surfaces

In daily life, we often measure how much space something covers or how long its boundary is. For example, we may want to know how much fencing is needed around a garden 🌱 or how much carpet is required to cover a room 🏠. Mathematics gives us clear ideas and methods to measure such quantities through the concepts of perimeter and area.

πŸ”΅ Perimeter deals with the boundary of a shape
🟒 Area deals with the surface covered by a shape
🟑 Both are essential for practical planning
πŸ”΄ This chapter builds strong measurement sense

🧠 2. What Is Perimeter?

The perimeter of a closed figure is the total length of its boundary.

πŸ”Ή It is found by adding the lengths of all sides
πŸ”Ή It tells us how far we go around a shape
πŸ”Ή Perimeter is measured in units of length (cm, m, km)

πŸ’‘ Concept:
Perimeter = sum of all sides

✏️ Note:
Perimeter is related to the outline, not the inside region.

🌱 3. Perimeter of Common Shapes

πŸ”΅ Perimeter of a square
πŸ”Ή All sides are equal
πŸ”Ή If one side = a, then perimeter = 4 Γ— a

🟒 Perimeter of a rectangle
πŸ”Ή Opposite sides are equal
πŸ”Ή If length = l and breadth = b
πŸ”Έ Perimeter = 2 Γ— (l + b)

πŸ’‘ Concept:
Equal sides simplify perimeter calculations.

🧠 4. Perimeter of Irregular Shapes

Not all shapes are regular.

πŸ”Ή Irregular shapes have sides of different lengths
πŸ”Ή Perimeter is found by adding all given sides
πŸ”Ή No special formula is needed

✏️ Note:
Careful addition is important to avoid mistakes.

🌿 5. Units of Perimeter

Perimeter is always measured in linear units.

πŸ”΅ Common units: centimetre, metre, kilometre
🟒 Smaller shapes use cm, larger ones use m or km
🟑 Units must be same before adding lengths

πŸ’‘ Concept:
Never add lengths with different units directly.

🧠 6. What Is Area?

The area of a figure is the amount of surface it covers.

πŸ”Ή It shows how much space lies inside a shape
πŸ”Ή Area is measured in square units
πŸ”Ή Examples: square centimetre, square metre

πŸ’‘ Concept:
Area = surface covered inside a boundary

✏️ Note:
Area always uses square units.

🌱 7. Area of a Rectangle

A rectangle covers space in rows and columns.

πŸ”΅ Length shows number of units along one direction
🟒 Breadth shows number of units along the other direction
🟑 Area = length Γ— breadth

πŸ”Ή If l = 6 cm and b = 4 cm
πŸ”Έ Area = 6 Γ— 4 = 24 square cm

πŸ’‘ Concept:
Area of rectangle = l Γ— b

🧠 8. Area of a Square

A square is a special rectangle.

πŸ”΅ All sides are equal
🟒 If side = a
πŸ”Έ Area = a Γ— a = aΒ²

✏️ Note:
Square area grows faster than perimeter as side increases.

🌿 9. Units of Area

Area is measured in square units.

πŸ”΅ Small areas β†’ square centimetre
🟒 Larger areas β†’ square metre
🟑 Very large areas β†’ hectare or square kilometre

πŸ’‘ Concept:
Area unit = (length unit)Β²

🧠 10. Difference Between Perimeter and Area

Understanding the difference is very important.

πŸ”΅ Perimeter measures boundary length
🟒 Area measures surface covered
🟑 Perimeter uses linear units
πŸ”΄ Area uses square units

✏️ Note:
Two shapes may have same perimeter but different areas.

🌍 11. Perimeter and Area in Daily Life

These concepts are used everywhere.

πŸ”΅ Fencing a field β†’ perimeter
🟒 Laying tiles on floor β†’ area
🟑 Painting a wall β†’ area
πŸ”΄ Wiring around a park β†’ perimeter

πŸ’‘ Concept:
Measurement helps in saving time, money, and resources.

🧠 12. Importance of Perimeter and Area

This chapter helps students:

πŸ”Ή Measure boundaries accurately
πŸ”Ή Calculate space correctly
πŸ”Ή Understand geometry practically
πŸ”Ή Prepare for advanced topics like mensuration

πŸ’‘ Concept:
Perimeter and area connect mathematics with real life.

πŸ“˜ Summary

The chapter Perimeter and Area introduces two important measurement concepts. Perimeter is the total length of the boundary of a closed figure, while area is the measure of the surface enclosed by that boundary. Students learn how to calculate the perimeter of squares, rectangles, and irregular shapes by adding side lengths. Area is understood as the space covered inside a shape and is measured in square units.

The formulas for the area of a rectangle and a square are explained clearly. The chapter also highlights the difference between perimeter and area and shows their importance in daily life situations like fencing, flooring, and painting. These ideas form the foundation for further study in geometry and mensuration.

πŸ“ Quick Recap

🟒 Perimeter is the total boundary length
🟑 Area is the surface covered
πŸ”΅ Square perimeter = 4 Γ— side
πŸ”΄ Rectangle area = length Γ— breadth
⚑ Area uses square units
🧠 These concepts are used in daily life

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TEXTBOOK QUESTIONS

🌿 FIGURE IT OUT

🌿 BASED ON PERIMETER

πŸ”’ ❓ Question 1.
Find the missing terms:

πŸ”’ ❓ (a) Perimeter of a rectangle = 14 cm; breadth = 2 cm; length = ?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Formula of perimeter of rectangle
Perimeter = 2 Γ— (length + breadth)

πŸ”΅ Step 2: Substitute given values
14 = 2 Γ— (length + 2)

πŸ”΅ Step 3: Divide both sides by 2
7 = length + 2

πŸ”΅ Step 4: Subtract 2
length = 5

βœ”οΈ Final: Length = 5 cm

πŸ”’ ❓ (b) Perimeter of a square = 20 cm; side of a length = ?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Formula of perimeter of square
Perimeter = 4 Γ— side

πŸ”΅ Step 2: Substitute value
20 = 4 Γ— side

πŸ”΅ Step 3: Divide by 4
side = 5

βœ”οΈ Final: Side = 5 cm

πŸ”’ ❓ (c) Perimeter of a rectangle = 12 m; length = 3 m; breadth = ?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Perimeter = 2 Γ— (length + breadth)

πŸ”΅ Step 2: Substitute values
12 = 2 Γ— (3 + breadth)

πŸ”΅ Step 3: Divide both sides by 2
6 = 3 + breadth

πŸ”΅ Step 4: Subtract 3
breadth = 3

βœ”οΈ Final: Breadth = 3 m

πŸ”’ ❓ Question 2.
A rectangle having sidelengths 5 cm and 3 cm is made using a piece of wire. If the wire is straightened and then bent to form a square, what will be the length of a side of the square?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Find perimeter of rectangle
Perimeter = 2 Γ— (5 + 3) = 2 Γ— 8 = 16 cm

πŸ”΅ Step 2: Same wire forms square, so perimeter remains same
Perimeter of square = 16 cm

πŸ”΅ Step 3: Side of square = Perimeter Γ· 4
Side = 16 Γ· 4 = 4

βœ”οΈ Final: Side of square = 4 cm

πŸ”’ ❓ Question 3.
Find the length of the third side of a triangle having a perimeter of 55 cm and having two sides of length 20 cm and 14 cm.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Perimeter of triangle
Perimeter = sum of all three sides

πŸ”΅ Step 2: Substitute values
55 = 20 + 14 + third side

πŸ”΅ Step 3: Add known sides
55 = 34 + third side

πŸ”΅ Step 4: Subtract 34
third side = 21

βœ”οΈ Final: Third side = 21 cm

πŸ”’ ❓ Question 4.
What would be the cost of fencing a rectangular park whose length is 150 m and breadth is 120 m, if the fence costs β‚Ή40 per metre?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Find perimeter of the park
Perimeter = 2 Γ— (150 + 120)
= 2 Γ— 270
= 540 m

πŸ”΅ Step 2: Cost per metre = β‚Ή40

πŸ”΅ Step 3: Total cost
= 540 Γ— 40
= 21600

βœ”οΈ Final: Cost = β‚Ή21,600

πŸ”’ ❓ Question 5.
A piece of string is 36 cm long. What will be the length of each side, if it is used to form:

πŸ”’ ❓ (a) A square

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Perimeter of square = 36 cm
πŸ”΅ Step 2: Side = 36 Γ· 4 = 9

βœ”οΈ Final: Each side = 9 cm

πŸ”’ ❓ (b) A triangle with all sides of equal length

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Perimeter of triangle = 36 cm
πŸ”΅ Step 2: Number of sides = 3
πŸ”΅ Step 3: Side = 36 Γ· 3 = 12

βœ”οΈ Final: Each side = 12 cm

πŸ”’ ❓ (c) A hexagon with sides of equal length

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Perimeter of hexagon = 36 cm
πŸ”΅ Step 2: Number of sides = 6
πŸ”΅ Step 3: Side = 36 Γ· 6 = 6

βœ”οΈ Final: Each side = 6 cm

πŸ”’ ❓ Question 6.
A farmer has a rectangular field having length 230 m and breadth 160 m. He wants to fence it with 3 rounds of rope as shown. What is the total length of rope needed?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Perimeter of the field
Perimeter = 2 Γ— (230 + 160)
= 2 Γ— 390
= 780 m

πŸ”΅ Step 2: Number of rounds = 3

πŸ”΅ Step 3: Total rope needed
= 3 Γ— 780
= 2340

βœ”οΈ Final: Total length of rope = 2340 m

🌿 MATHA PACHCHI!

πŸ”’ ❓ Question 1.
Find out the total distance Akshi has covered in 5 rounds.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Akshi runs on the outer rectangular track
πŸ”΅ Step 2: Length = 70 m, Breadth = 40 m
πŸ”΅ Step 3: Perimeter of rectangle
Perimeter = 2 Γ— (length + breadth)
= 2 Γ— (70 + 40)
= 2 Γ— 110
= 220 m

πŸ”΅ Step 4: Distance covered in 5 rounds
= 5 Γ— 220
= 1100 m

βœ”οΈ Final: Akshi covered 1100 m in 5 rounds

πŸ”’ ❓ Question 2.
Find out the total distance Toshi has covered in 7 rounds. Who ran a longer distance?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Toshi runs on the inner rectangular track
πŸ”΅ Step 2: Length = 60 m, Breadth = 30 m
πŸ”΅ Step 3: Perimeter of inner track
Perimeter = 2 Γ— (60 + 30)
= 2 Γ— 90
= 180 m

πŸ”΅ Step 4: Distance covered in 7 rounds
= 7 Γ— 180
= 1260 m

πŸ”΅ Step 5: Compare distances
Akshi = 1100 m
Toshi = 1260 m

βœ”οΈ Final: Toshi ran a longer distance

πŸ”’ ❓ Question 3.
Think and mark the positions as directedβ€”

πŸ”’ ❓ (a) Mark β€˜A’ at the point where Akshi will be after she ran 250 m.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: One full round of Akshi = 220 m
πŸ”΅ Step 2: After 250 m, extra distance = 250 βˆ’ 220 = 30 m
πŸ”΅ Step 3: Starting from Akshi’s starting point, move 30 m along the track

βœ”οΈ Final: Point A is 30 m ahead of Akshi’s starting point on the outer track

πŸ”’ ❓ (b) Mark β€˜B’ at the point where Akshi will be after she ran 500 m.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: One round = 220 m
πŸ”΅ Step 2: Distance after 2 rounds = 2 Γ— 220 = 440 m
πŸ”΅ Step 3: Extra distance = 500 βˆ’ 440 = 60 m

βœ”οΈ Final: Point B is 60 m ahead of Akshi’s starting point on the outer track

πŸ”’ ❓ (c) Now, Akshi ran 1000 m. How many full rounds has she finished running around her track? Mark her position as β€˜C’.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: One round = 220 m
πŸ”΅ Step 2: Number of full rounds
1000 Γ· 220 = 4 full rounds (remainder left)

πŸ”΅ Step 3: Distance after 4 rounds
= 4 Γ— 220 = 880 m
πŸ”΅ Step 4: Extra distance = 1000 βˆ’ 880 = 120 m

βœ”οΈ Final:
β€’ Akshi completed 4 full rounds
β€’ Point C is 120 m ahead of her starting point

πŸ”’ ❓ (d) Mark β€˜X’ at the point where Toshi will be after she ran 250 m.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: One round of Toshi = 180 m
πŸ”΅ Step 2: Extra distance after one round
= 250 βˆ’ 180 = 70 m

βœ”οΈ Final: Point X is 70 m ahead of Toshi’s starting point on the inner track

πŸ”’ ❓ (e) Mark β€˜Y’ at the point where Toshi will be after she ran 500 m.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Two rounds = 2 Γ— 180 = 360 m
πŸ”΅ Step 2: Extra distance = 500 βˆ’ 360 = 140 m

βœ”οΈ Final: Point Y is 140 m ahead of Toshi’s starting point on the inner track

πŸ”’ ❓ (f) Now, Toshi ran 1000 m. How many full rounds has she finished running around her track? Mark her position as β€˜Z’.

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: One round = 180 m
πŸ”΅ Step 2: Number of full rounds
1000 Γ· 180 = 5 full rounds

πŸ”΅ Step 3: Distance after 5 rounds
= 5 Γ— 180 = 900 m
πŸ”΅ Step 4: Extra distance = 1000 βˆ’ 900 = 100 m

βœ”οΈ Final:
β€’ Toshi completed 5 full rounds
β€’ Point Z is 100 m ahead of her starting point

🌿 AREA

πŸ”’ ❓ Question 1.
The area of a rectangular garden 25 m long is 300 sq m. What is the width of the garden?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Formula for area of a rectangle
Area = length Γ— width

πŸ”΅ Step 2: Substitute given values
300 = 25 Γ— width

πŸ”΅ Step 3: Divide both sides by 25
width = 300 Γ· 25

πŸ”΅ Step 4: Calculate
width = 12

βœ”οΈ Final: Width of the garden = 12 m

πŸ”’ ❓ Question 2.
What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of β‚Ή8 per hundred sq m?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Find area of the plot
Area = 500 Γ— 200 = 100000 sq m

πŸ”΅ Step 2: Rate given is β‚Ή8 per 100 sq m

πŸ”΅ Step 3: Number of 100 sq m units
100000 Γ· 100 = 1000

πŸ”΅ Step 4: Find total cost
Cost = 1000 Γ— 8

βœ”οΈ Final: Cost of tiling = β‚Ή8000

πŸ”’ ❓ Question 3.
A rectangular coconut grove is 100 m long and 50 m wide. If each coconut tree requires 25 sq m, what is the maximum number of trees that can be planted in this grove?

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Find area of the grove
Area = 100 Γ— 50 = 5000 sq m

πŸ”΅ Step 2: Area required per tree = 25 sq m

πŸ”΅ Step 3: Number of trees
Number of trees = 5000 Γ· 25

πŸ”΅ Step 4: Calculate
Number of trees = 200

βœ”οΈ Final: Maximum number of trees = 200

πŸ”’ ❓ Question 4.
By splitting the following figures into rectangles, find their areas (all measures are given in metres).

πŸ”’ ❓ (a)

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Split the figure into three rectangles

πŸ”΅ Rectangle 1 (bottom left):
Length = 3 m, Breadth = 4 m
Area = 3 Γ— 4 = 12 sq m

πŸ”΅ Rectangle 2 (middle):
Length = 4 m, Breadth = 3 m
Area = 4 Γ— 3 = 12 sq m

πŸ”΅ Rectangle 3 (top right):
Length = 3 m, Breadth = 1 m
Area = 3 Γ— 1 = 3 sq m

πŸ”΅ Step 2: Add all areas
Total area = 12 + 12 + 3

βœ”οΈ Final: Area of figure (a) = 27 sq m

πŸ”’ ❓ (b)

πŸ“Œ βœ… Answer:
πŸ”΅ Step 1: Treat the figure as a big rectangle minus a small rectangle

πŸ”΅ Big rectangle:
Length = 5 m, Breadth = 3 m
Area = 5 Γ— 3 = 15 sq m

πŸ”΅ Inner cut rectangle:
Length = 3 m, Breadth = 2 m
Area = 3 Γ— 2 = 6 sq m

πŸ”΅ Step 2: Subtract inner area
Required area = 15 βˆ’ 6

βœ”οΈ Final: Area of figure (b) = 9 sq m

FIGURE IT OUT

πŸ”’ ❓ Question 1
Explore and figure out how many pieces have the same area.

πŸ“Œ βœ… Answer:
πŸ”Ή To compare areas, we place one tangram piece over another.
πŸ”Ή If two pieces completely cover each other, their areas are equal.
πŸ”Ή On careful observation:
πŸ”Έ Shape A and Shape B cover each other exactly.
πŸ”Έ Shape C and Shape E also cover each other exactly.

βœ”οΈ Conclusion:
πŸ”Ή A and B have the same area.
πŸ”Ή C and E have the same area.

πŸ”’ ❓ Question 2
How many times bigger is Shape D as compared to Shape C?
What is the relationship between Shapes C, D and E?

πŸ“Œ βœ… Answer:
πŸ”Ή When Shape C and Shape E are placed together, they fit perfectly into Shape D.
πŸ”Ή This shows that Shape D is made of two equal smaller pieces.

βœ”οΈ Therefore:
πŸ”Ή Area of D = Area of C + Area of E
πŸ”Ή Area of D = 2 Γ— Area of C

βœ”οΈ Relationship:
πŸ”Ή C and E have equal area.
πŸ”Ή D has twice the area of C and E.

πŸ”’ ❓ Question 3
Which shape has more area: Shape D or Shape F? Give reasons.

πŸ“Œ βœ… Answer:
πŸ”Ή Shape D is formed using two small pieces (C and E).
πŸ”Ή Shape F is a larger piece and cannot be fully covered by Shape D.

βœ”οΈ Conclusion:
πŸ”Ή Shape F has more area than Shape D.

πŸ”’ ❓ Question 4
Which shape has more area: Shape F or Shape G? Give reasons.

πŸ“Œ βœ… Answer:
πŸ”Ή When Shape F and Shape G are rearranged and placed over each other, they cover the same region.
πŸ”Ή Rotation or flipping does not change area.

βœ”οΈ Conclusion:
πŸ”Ή Shape F and Shape G have equal area.

πŸ”’ ❓ Question 5
What is the area of Shape A as compared to Shape G?
Is it twice as big? Four times as big?

πŸ“Œ βœ… Answer:
πŸ”Ή By placing Shape G repeatedly on Shape A, we observe that two Shapes G exactly cover Shape A.

βœ”οΈ Therefore:
πŸ”Ή Area of A = 2 Γ— Area of G

βœ”οΈ Shape A is twice as big as Shape G.

πŸ”’ ❓ Question 6
Find the area of the big square formed with all seven pieces in terms of the area of Shape C.

πŸ“Œ βœ… Answer:
πŸ”Ή Let the area of Shape C be 1 unit.

πŸ”Ή From comparisons:
πŸ”Ή C = 1 unit
πŸ”Ή E = 1 unit
πŸ”Ή D = 2 units
πŸ”Ή A = 2 units
πŸ”Ή B = 2 units
πŸ”Ή F = 2 units
πŸ”Ή G = 2 units

πŸ”Ή Total area of big square
= 1 + 1 + 2 + 2 + 2 + 2 + 2
= 12 units

βœ”οΈ Area of the big square = 12 times the area of Shape C.

πŸ”’ ❓ Question 7
Arrange the 7 pieces to form a rectangle.
What will be the area of this rectangle in terms of the area of Shape C? Give reasons.

πŸ“Œ βœ… Answer:
πŸ”Ή Rearranging pieces changes the shape, not the area.
πŸ”Ή All seven pieces are still used completely.

βœ”οΈ Therefore:
πŸ”Ή Area of rectangle = 12 Γ— area of Shape C.

πŸ”’ ❓ Question 8
Are the perimeters of the square and the rectangle formed from these 7 pieces different or the same? Explain.

πŸ“Œ βœ… Answer:
πŸ”Ή Area depends on how many pieces are used.
πŸ”Ή Perimeter depends on the outer boundary of the shape.
πŸ”Ή A square and a rectangle have different outer boundaries.

βœ”οΈ Conclusion:
πŸ”Ή Their perimeters are different, even though their areas are the same.

🌿 AREA OF TRIANGLE

πŸ”’ ❓ Question 1
Find the areas of the figures below by dividing them into rectangles and triangles.

πŸ“Œ βœ… Answer (Teacher-style explanation)
πŸ”Ή Each small square on the grid represents 1 square unit
πŸ”Ή Full squares are counted directly
πŸ”Ή Two half-squares together make 1 square unit
πŸ”Ή Add areas of all rectangles and triangles formed after splitting

πŸ”΅ Figure (a)
πŸ“Œ Split into one rectangle and two triangles
πŸ”Ή Rectangle area = 20 square units
πŸ”Ή Two triangles together = 4 square units
βœ”οΈ Total area = 24 square units

πŸ”΅ Figure (b)
πŸ“Œ Split into one rectangle and one triangle
πŸ”Ή Rectangle area = 24 square units
πŸ”Ή Triangle area = 6 square units
βœ”οΈ Total area = 30 square units

πŸ”΅ Figure (c)
πŸ“Œ Split into one large rectangle and two triangles
πŸ”Ή Rectangle area = 36 square units
πŸ”Ή Two triangles together = 8 square units
βœ”οΈ Total area = 44 square units

πŸ”΅ Figure (d)
πŸ“Œ Split into one rectangle and two triangles
πŸ”Ή Rectangle area = 20 square units
πŸ”Ή Two triangles together = 6 square units
βœ”οΈ Total area = 26 square units

πŸ”΅ Figure (e)
πŸ“Œ Split into two equal triangles
πŸ”Ή Each triangle = 6 square units
βœ”οΈ Total area = 12 square units

βœ”οΈ Final Answers (in square units)
πŸ”Ή (a) 24
πŸ”Ή (b) 30
πŸ”Ή (c) 44
πŸ”Ή (d) 26
πŸ”Ή (e) 12

🌿 AREA MAZE PUZZLES

πŸ”’ ❓ Question
Area Maze Puzzles
In each figure, find the missing value of either the length of a side or the area of a region.

πŸ“Œ βœ… Answer (Teacher-style classroom explanation)

πŸ”’ ❓ (a)
(13 sq cm, 26 sq cm, 15 sq cm, ? sq cm)

πŸ“Œ βœ… Answer
πŸ”Ή The top-left and top-right rectangles have the same height.
πŸ”Ή So their areas are proportional to their widths.

πŸ”Ή 26 sq cm is double of 13 sq cm
πŸ”Ή So, top-right width is double of top-left width

πŸ”Ή Bottom-left area = 15 sq cm
πŸ”Ή Bottom-right will also be double (same widths as above)

πŸ”Ή Step 1: ? area = 2 Γ— 15
πŸ”Ή Step 2: ? area = 30
βœ”οΈ Final: 30 sq cm

πŸ”’ ❓ (b)
(10 sq cm at bottom, 10 sq cm vertical, top pink ? sq cm, with 3 cm and 2 cm markings)

πŸ“Œ βœ… Answer
πŸ”Ή Bottom rectangle has height = 2 cm (given).
πŸ”Ή Its area = 10 sq cm.

πŸ”Ή Step 1: Bottom length = Area Γ· height
πŸ”Ή Step 2: Bottom length = 10 Γ· 2 = 5 cm

πŸ”Ή The marked 3 cm is only the left part, so the remaining right part = 5 βˆ’ 3 = 2 cm
πŸ”Ή That 2 cm is the width of the vertical rectangle above (same strip).

πŸ”Ή Vertical rectangle area = 10 sq cm, width = 2 cm
πŸ”Ή Step 3: Vertical height = 10 Γ· 2 = 5 cm

πŸ”Ή The vertical gap shown next to the pink rectangle is 2 cm (given).
πŸ”Ή So, pink height = total height βˆ’ gap = 5 βˆ’ 2 = 3 cm

πŸ”Ή Pink top length = 3 cm (given)
πŸ”Ή Step 4: Pink area = 3 Γ— 3 = 9 sq cm
βœ”οΈ Final: 9 sq cm

πŸ”’ ❓ (c)
(Total height 15 cm, middle 42 sq cm with height 6 cm, bottom 60 sq cm, extra 5 cm on bottom, and 3 cm marking near top)

πŸ“Œ βœ… Answer
πŸ”Ή Middle rectangle area = 42 sq cm and its height = 6 cm (given).
πŸ”Ή Step 1: Middle width = 42 Γ· 6 = 7 cm

πŸ”Ή Bottom rectangle extends 5 cm more than the middle (given).
πŸ”Ή Step 2: Bottom width = 7 + 5 = 12 cm

πŸ”Ή Bottom rectangle area = 60 sq cm
πŸ”Ή Step 3: Bottom height = 60 Γ· 12 = 5 cm

πŸ”Ή Total height on left = 15 cm
πŸ”Ή Heights already used = bottom 5 cm + middle 6 cm = 11 cm
πŸ”Ή Step 4: Top (pink) height = 15 βˆ’ 11 = 4 cm

πŸ”Ή The 3 cm mark shows the middle is 3 cm wider than the top pink part.
πŸ”Ή So, top pink width = 7 βˆ’ 3 = 4 cm

πŸ”Ή Step 5: Pink area = 4 Γ— 4 = 16 sq cm
βœ”οΈ Final: 16 sq cm

πŸ”’ ❓ (d)
(Left rectangle 38 sq cm with top ? cm, right rectangle 18 sq cm with width 5 cm, and height difference 4 cm)

πŸ“Œ βœ… Answer
πŸ”Ή Right rectangle area = 18 sq cm and its width = 5 cm (given).
πŸ”Ή Step 1: Right height = 18 Γ· 5 = 3.6 cm

πŸ”Ή The left rectangle is 4 cm taller than the right one (given).
πŸ”Ή Step 2: Left height = 3.6 + 4 = 7.6 cm

πŸ”Ή Left rectangle area = 38 sq cm
πŸ”Ή Step 3: Left top length = Area Γ· height = 38 Γ· 7.6 = 5 cm
βœ”οΈ Final: 5 cm

βœ”οΈ Final Answers
πŸ”Ή (a) 30 sq cm
πŸ”Ή (b) 9 sq cm
πŸ”Ή (c) 16 sq cm
πŸ”Ή (d) 5 cm

🌿 FIGURE IT OUT

πŸ”’ ❓ Question 1
Give the dimensions of a rectangle whose area is the sum of the areas of these two rectangles having measurements: 5 m Γ— 10 m and 2 m Γ— 7 m.

πŸ“Œ βœ… Answer
Area of first rectangle = 5 Γ— 10 = 50 sq m

Area of second rectangle = 2 Γ— 7 = 14 sq m

Total area = 50 + 14 = 64 sq m

One rectangle having area 64 sq m can have
Length = 8 m
Breadth = 8 m

βœ”οΈ Final Answer
8 m Γ— 8 m

πŸ”’ ❓ Question 2
The area of a rectangular garden that is 50 m long is 1000 sq m. Find the width of the garden.

πŸ“Œ βœ… Answer
Area = Length Γ— Breadth

1000 = 50 Γ— Breadth

Breadth = 1000 Γ· 50

Breadth = 20

βœ”οΈ Final Answer
Width = 20 m

πŸ”’ ❓ Question 3
The floor of a room is 5 m long and 4 m wide. A square carpet whose sides are 3 m in length is laid on the floor. Find the area that is not carpeted.

πŸ“Œ βœ… Answer
Area of floor = 5 Γ— 4 = 20 sq m

Area of carpet = 3 Γ— 3 = 9 sq m

Area not carpeted = 20 βˆ’ 9

Area not carpeted = 11

βœ”οΈ Final Answer
11 sq m

πŸ”’ ❓ Question 4
Four flower beds having sides 2 m long and 1 m wide are dug at the four corners of a garden that is 15 m long and 12 m wide. How much area is now available for laying down a lawn?

πŸ“Œ βœ… Answer
Area of garden = 15 Γ— 12 = 180 sq m

Area of one flower bed = 2 Γ— 1 = 2 sq m

Area of four flower beds = 4 Γ— 2 = 8 sq m

Area available for lawn = 180 βˆ’ 8

Area available for lawn = 172

βœ”οΈ Final Answer
172 sq m

πŸ”’ ❓ Question 5
Shape A has an area of 18 square units and Shape B has an area of 20 square units. Shape A has a longer perimeter than Shape B. Draw two such shapes satisfying the given conditions.

πŸ“Œ βœ… Answer
Take Shape A as a rectangle of size 1 Γ— 18

Area of Shape A = 18 square units
Perimeter of Shape A = 2(1 + 18) = 38 units

Take Shape B as a rectangle of size 4 Γ— 5

Area of Shape B = 20 square units
Perimeter of Shape B = 2(4 + 5) = 18 units

Shape A has smaller area but larger perimeter

βœ”οΈ Final Answer
Shape A: 1 Γ— 18
Shape B: 4 Γ— 5

πŸ”’ ❓ Question 6
On a page in your book, draw a rectangular border that is 1 cm from the top and bottom and 1.5 cm from the left and right sides. What is the perimeter of the border?

πŸ“Œ βœ… Answer
Let the page length be L cm and breadth be B cm

Border length = L βˆ’ 2

Border breadth = B βˆ’ 3

Perimeter of border = 2[(L βˆ’ 2) + (B βˆ’ 3)]

βœ”οΈ Final Answer
Perimeter = 2(L + B βˆ’ 5) cm

πŸ”’ ❓ Question 7
Draw a rectangle of size 12 units Γ— 8 units. Draw another rectangle inside it, without touching the outer rectangle, that occupies exactly half the area.

πŸ“Œ βœ… Answer
Area of outer rectangle = 12 Γ— 8 = 96 sq units

Half of the area = 96 Γ· 2 = 48 sq units

One possible inner rectangle is 6 Γ— 8

βœ”οΈ Final Answer
Inner rectangle area = 48 sq units

πŸ”’ ❓ Question 8
A square piece of paper is folded in half. The square is then cut into two rectangles along the fold. Which statement is always true?

πŸ“Œ βœ… Answer
Let side of square = a

Area of square = aΒ²

After folding, each rectangle has area = aΒ² Γ· 2

Perimeter of square = 4a

Each rectangle has dimensions a and a/2

Perimeter of one rectangle = 2(a + a/2) = 3a

Perimeter of two rectangles together = 6a

6a = 1Β½ Γ— 4a

βœ”οΈ Final Answer
Correct option is (c)

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OTHER IMPORTANT QUESTIONS

(CBSE MODEL QUESTION PAPER)

ESPECIALLY MADE FROM THIS CHAPTER ONLY

πŸ”΅ Section A β€” Very Short Answer (1 mark each)

πŸ”’ ❓ Question 1
What is meant by the perimeter of a figure?

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter is the total length of the boundary of a closed figure

πŸ”’ ❓ Question 2
In which units is perimeter measured?

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter is measured in units of length like cm or m

πŸ”’ ❓ Question 3
What is the perimeter of a square of side 5 cm?

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter of square = 4 Γ— side
πŸ”Έ Perimeter = 4 Γ— 5 = 20 cm

πŸ”’ ❓ Question 4
Name the shape whose opposite sides are equal.

πŸ“Œ βœ… Answer:
πŸ”Ή Rectangle

πŸ”’ ❓ Question 5
What is meant by area?

πŸ“Œ βœ… Answer:
πŸ”Ή Area is the amount of surface covered by a figure

πŸ”’ ❓ Question 6
True or False:
Area is measured in square units.

πŸ“Œ βœ… Answer:
πŸ”Ή Area always uses square units
βœ”οΈ Final: True

🟒 Section B β€” Short Answer I (2 marks each)

πŸ”’ ❓ Question 7
Write the formula for the perimeter of a rectangle.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter of rectangle = 2 Γ— (length + breadth)

πŸ”’ ❓ Question 8
Find the perimeter of a rectangle whose length is 6 cm and breadth is 4 cm.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter = 2 Γ— (6 + 4)
πŸ”Έ Perimeter = 2 Γ— 10 = 20 cm

πŸ”’ ❓ Question 9
What is the formula for the area of a square?

πŸ“Œ βœ… Answer:
πŸ”Ή Area of square = side Γ— side

πŸ”’ ❓ Question 10
Find the area of a square of side 7 cm.

πŸ“Œ βœ… Answer:
πŸ”Ή Area = 7 Γ— 7
πŸ”Έ Area = 49 square cm

πŸ”’ ❓ Question 11
Write one difference between perimeter and area.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter measures boundary length
πŸ”Έ Area measures surface covered

πŸ”’ ❓ Question 12
Mention one daily-life situation where perimeter is used.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter is used to find fencing required around a field

🟑 Section C β€” Short Answer II (3 marks each)

πŸ”’ ❓ Question 13
Define perimeter and write its formula for a square.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter is the total length of the boundary of a closed figure
πŸ”Ή A square has four equal sides
πŸ”Έ Perimeter of a square = 4 Γ— side

πŸ”’ ❓ Question 14
Find the perimeter of a square whose side is 9 cm.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter of square = 4 Γ— side
πŸ”Ή Perimeter = 4 Γ— 9
πŸ”Έ Perimeter = 36 cm

πŸ”’ ❓ Question 15
Write the formula for the area of a rectangle and explain its terms.

πŸ“Œ βœ… Answer:
πŸ”Ή Area of rectangle = length Γ— breadth
πŸ”Ή Length shows the longer side
πŸ”Έ Breadth shows the shorter side

πŸ”’ ❓ Question 16
Find the area of a rectangle whose length is 8 cm and breadth is 5 cm.

πŸ“Œ βœ… Answer:
πŸ”Ή Area = length Γ— breadth
πŸ”Ή Area = 8 Γ— 5
πŸ”Έ Area = 40 square cm

πŸ”’ ❓ Question 17
State two differences between perimeter and area.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter measures boundary length, area measures surface covered
πŸ”Έ Perimeter uses linear units, area uses square units

πŸ”’ ❓ Question 18
Why are the units of area written as square units?

πŸ“Œ βœ… Answer:
πŸ”Ή Area is measured using squares of unit length
πŸ”Ή It shows how many unit squares cover a surface
πŸ”Έ Hence, units are written as square units

πŸ”’ ❓ Question 19
Can two figures have the same perimeter but different areas? Explain.

πŸ“Œ βœ… Answer:
πŸ”Ή Yes, figures can have the same boundary length
πŸ”Ή But their shapes may be different
πŸ”Έ Hence, the surface covered can be different

πŸ”’ ❓ Question 20
Write one example each where perimeter and area are used in daily life.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter is used to calculate fencing around a garden
πŸ”Έ Area is used to calculate carpet needed for a room

πŸ”’ ❓ Question 21
Find the perimeter of a rectangle whose length is 10 m and breadth is 6 m.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter = 2 Γ— (length + breadth)
πŸ”Ή Perimeter = 2 Γ— (10 + 6)
πŸ”Έ Perimeter = 32 m

πŸ”’ ❓ Question 22
Why is it important to use the same units while finding perimeter or area?

πŸ“Œ βœ… Answer:
πŸ”Ή Different units cannot be added or multiplied directly
πŸ”Ή Using same units avoids calculation errors
πŸ”Έ It gives correct and meaningful results

πŸ”΄ Section D β€” Long Answer (4 marks each)

πŸ”’ ❓ Question 23
Explain how to find the perimeter of an irregular shape.

πŸ“Œ βœ… Answer:
πŸ”Ή An irregular shape has sides of different lengths
πŸ”Ή Measure the length of each side carefully
πŸ”Ή Add the lengths of all sides together
πŸ”Έ The total sum gives the perimeter of the irregular shape
βœ”οΈ Final: Perimeter = sum of all side lengths

πŸ”’ ❓ Question 24
Find the perimeter of a rectangle whose length is 12 cm and breadth is 8 cm. Show all steps.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter of rectangle = 2 Γ— (length + breadth)
πŸ”Ή Perimeter = 2 Γ— (12 + 8)
πŸ”Ή Perimeter = 2 Γ— 20
πŸ”Έ Perimeter = 40 cm
βœ”οΈ Final: Perimeter of the rectangle is 40 cm

πŸ”’ ❓ Question 25
Explain the method of finding the area of a rectangle with an example.

πŸ“Œ βœ… Answer:
πŸ”Ή A rectangle is covered by rows and columns of unit squares
πŸ”Ή Length shows number of squares in one row
πŸ”Ή Breadth shows number of rows
πŸ”Έ Area of rectangle = length Γ— breadth
πŸ”Έ Example: If length = 6 cm and breadth = 5 cm
πŸ”Έ Area = 6 Γ— 5 = 30 square cm
βœ”οΈ Final: Area is found by multiplying length and breadth

πŸ”’ ❓ Question 26
Explain the difference between perimeter and area using a suitable example.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter measures the boundary length of a figure
πŸ”Ή Area measures the surface covered inside the figure
πŸ”Ή Example: A square of side 4 cm
πŸ”Ή Perimeter = 4 Γ— 4 = 16 cm
πŸ”Έ Area = 4 Γ— 4 = 16 square cm
βœ”οΈ Final: Perimeter and area measure different quantities

πŸ”’ ❓ Question 27
OR
Can two figures have the same area but different perimeters? Explain.

πŸ“Œ βœ… Answer:
πŸ”Ή Yes, two figures can cover the same surface area
πŸ”Ή Their shapes may be different
πŸ”Ή Different shapes can have different boundary lengths
πŸ”Έ Hence, perimeters can be different even if area is same
βœ”οΈ Final: Same area does not guarantee same perimeter

πŸ”’ ❓ Question 28
Explain why area is measured in square units.

πŸ“Œ βœ… Answer:
πŸ”Ή Area is found by counting unit squares that cover a surface
πŸ”Ή Each unit square has length and breadth of one unit
πŸ”Ή This gives square units like cmΒ² or mΒ²
πŸ”Έ Square units show two-dimensional measurement
βœ”οΈ Final: Area uses square units because it measures surface

πŸ”’ ❓ Question 29
Explain with examples how perimeter and area are used in daily life.

πŸ“Œ βœ… Answer:
πŸ”Ή Perimeter is used to calculate fencing around a field
πŸ”Ή Area is used to find the amount of tiles needed for flooring
πŸ”Ή Area is used in painting walls
πŸ”Έ Perimeter is used in placing wires or boundaries
βœ”οΈ Final: These measurements help in planning and saving resources

πŸ”’ ❓ Question 30
OR
A room is 7 m long and 5 m wide.
(i) Find the perimeter of the room
(ii) Find the area of the room

πŸ“Œ βœ… Answer:
πŸ”Ή (i) Perimeter = 2 Γ— (length + breadth)
πŸ”Ή Perimeter = 2 Γ— (7 + 5)
πŸ”Ή Perimeter = 2 Γ— 12 = 24 m

πŸ”Ή (ii) Area = length Γ— breadth
πŸ”Ή Area = 7 Γ— 5 = 35 square m

βœ”οΈ Final:
πŸ”Ή Perimeter = 24 m
πŸ”Έ Area = 35 square m

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